題目:
(M90H010) 2^x個位數疊加 : 輸入一整數n,計算 21+22+23+24+...+2n之個位數。輸入:
90輸出:
6
#include <stdio.h>
int main(){
int index,i=1,sum=0;
scanf("%d",&index);
while(i<=index){
switch(i%4){
case 1:
sum+=2;
break;
case 2:
sum+=4;
break;
case 3:
sum+=8;
break;
default:
sum+=6;
}
i++;
}
printf("%d",sum%10);
return 0;
}